[Haskell-beginners] How to show a record
martin
martin.drautzburg at web.de
Sun Aug 17 09:40:27 UTC 2014
Right, but this is merely a coincidence.
What I wanted is a way to show a value of a record, where all fields are instances of Show.
Haskell itself is able to do this (and it even figures out the accessors, which I am not even asking for).
Am 08/16/2014 12:39 PM, schrieb Roman Czyborra:
> Your particular types do not require your annoying repetition beyond
> [ show . pType, accepts, produces, workarea] with 1st show = (:[])
>
>
>
> On Sat, Aug 16, 2014 at 10:45 AM, martin <martin.drautzburg at web.de <mailto:martin.drautzburg at web.de>> wrote:
>
> Hello all,
>
> I have a record type like this
>
> data Payload = Pl {
> pType :: Char,
> accepts :: String,
> produces :: String,
> workarea :: String} deriving (Eq)
>
> an I want to write my own show function. I ended up with somethink like this
>
> show pl = concatMap ( $ pl) [show . pType, show . accepts, show . produces, show . workarea]
>
> That repetition of "show ." annoys me, but of course without it the elements of that list would have different types. Is
> there a way around it and how does haskell itself manage to show records?
> _______________________________________________
> Beginners mailing list
> Beginners at haskell.org <mailto:Beginners at haskell.org>
> http://www.haskell.org/mailman/listinfo/beginners
>
>
>
>
> _______________________________________________
> Beginners mailing list
> Beginners at haskell.org
> http://www.haskell.org/mailman/listinfo/beginners
>
More information about the Beginners
mailing list