[Haskell-beginners] Why is it so slow to solve "10^(10^10)"?

[Brandon Allbery]

On Sun, Sep 22, 2013 at 12:50 AM, Graham Gill <math.simplex at gmail.com>wrote:

>  10^(10^10) is a 1 followed by ten billion zeros. Naively evaluating that
> to an integer is going to cause time and memory problems in any software
> that supports arbitrary size integers - as Bob Ippolito said, it's
>

I wonder if they were looking for (**) instead of (^).

-- 
brandon s allbery kf8nh                               sine nomine associates
allbery.b at gmail.com                                  ballbery at sinenomine.net
unix, openafs, kerberos, infrastructure, xmonad        http://sinenomine.net
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