[Haskell-beginners] point-free + IO Monad

[Tony Morris]

You can drop the parens if you like.

f2 a = putStrLn . f1 =<< a -- my preference

f2 a = a >>= putStrLn . f1
 On 31/03/2013 7:29 PM, "Ovidiu D" <ovidiudeac at gmail.com> wrote:

> That's good enough. Thanks!
>
>
> On Sun, Mar 31, 2013 at 11:08 AM, Franco <franco00 at gmx.com> wrote:
>
>> Ovidiu D <ovidiudeac <at> gmail.com> writes:
>>
>> >
>> > I have the following code:
>> >
>> > f1 :: String -> String
>> >
>> > f2 :: IO String -> IO ()
>> > f2 a = do
>> >    b <- a
>> >    putStr $ f1 b
>> >
>> > How can I write the function f2 in a point-free style?
>> >
>>
>> maybe
>>
>> f2 = (=<<) (putStrLn . f1)
>>
>> I still prefer the non point-free but clearer
>>
>> f2 = a >>= (putStrLn . f1)
>>
>>
>>
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