[Haskell-beginners] How to get each list in a list of lists for filter
Harald Bögeholz
bo at ct.de
Tue Dec 31 20:34:44 UTC 2013
Am 31.12.13 19:48, schrieb Angus Comber:
> I am getting a list of lists from chop9. I want to somehow filter each
> element in the list. How do I do that.
>
> I have encoded binary data eg [1,1,0,0,1,0] etc
>
> Each 9th bit is a parity bit which is checked using this function:
>
> type Bit = Int
>
> paritychecker :: [Bit] -> Bool
> paritychecker xs | length xs == 9 && ((sum (init xs)) `mod` 2) == (last xs)
> = True
> | otherwise = False
>
>
> In the stream (the list) I use chop to retrieve each block of 9 bits as in:
>
> chop9 :: [Bit] -> [[Bit]]
> chop9 [] = []
> chop9 bits = take 8 bits : chop9 (drop 8 bits)
>
> I have been playing with this sort of thing:
> filter paritychecker ??? chop9 [1,0,0,0,1,1,1,0,0,...]
>
> But doesn't work.
Could a simple typo be the problem?
Shouldn't chop9 .. take 9 bits ... and ... drop 9 bits ... instead of 8?
Harald
--
Harald Bögeholz <bo at ct.de> (PGP key available from servers)
Redaktion c't Tel.: +49 511 5352-300 Fax: +49 511 5352-417
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int f[9814],b,c=9814,g,i;long a=1e4,d,e,h;
main(){for(;b=c,c-=14;i=printf("%04d",e+d/a),e=d%a)
while(g=--b*2)d=h*b+a*(i?f[b]:a/5),h=d/--g,f[b]=d%g;}
(Arndt/Haenel)
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