[Haskell-beginners] Thread Blocking
Eugene Perederey
eugene.perederey at gmail.com
Tue Sep 4 21:02:51 CEST 2012
Why do you think main should block more than once?
I see only two possible scenarios: the fun thread puts to mvar first
thus blocking main,
or 10 is put into mvar in main, blocking the other thread indefinitely.
On 4 September 2012 11:54, mukesh tiwari <mukeshtiwari.iiitm at gmail.com> wrote:
> Hello All
> I was going trough Real World Haskell and it says "If we try to put a value
> into an MVar that is already full, our thread is put to sleep until another
> thread takes the value out". I wrote a simple code to block main
>
> import Data.List
> import Control.Concurrent
>
> fun m = do
> putMVar m 10
> return ()
>
>
> main = do
> m <- newEmptyMVar
> forkIO $ fun m
> putMVar m 10
> return ()
>
> What I am expecting that main should be blocked at least couple of times
> but its behaving more deterministically.
> [mukesh.tiwari@ Programming]$ ghc-7.4.1 -threaded -fforce-recomp
> Concurrent.hs
> [1 of 1] Compiling Main ( Concurrent.hs, Concurrent.o )
> Linking Concurrent ...
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$ ./Concurrent +RTS -N2
> [mukesh.tiwari@ Programming]$
>
> I am expecting to get thread blocked indefinitely on MVar at least half the
> time. Could some one please tell me why this deterministic behavior ?
> Regards
> Mukesh Tiwari
>
>
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--
Best,
Eugene Perederey
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