[Haskell-beginners] arbitrary rank polymorphism and ghc language pragmas

[rickmurphy]

Hi All:

I've been working through some details in these papers [1], [2] and
noticed a language pragma configuration that I hope you can confirm.

When using explicit foralls in a data constructor, it appears that GHC
7.4.2 requires Rank2Types in the Language pragma for what the papers
consider rank 1 types. 

Here's an example:

data T = TC (forall a b. a -> b -> a)

Am I correct, or is there another extension? The ExplicitForAll does not
appear to support rank 1 types in data constructors.

1. Practical Type Inference for Arbitrary-Rank Types.
2. A Direct Algorithm for Type Inference in the Rank 2 Fragment of the
Second-Order Lambda Calculus.

--
Rick