[Haskell-beginners] The application of application

[Christopher Howard]

On 12/01/2012 01:31 PM, Christopher Howard wrote:
> Can application of an expression (to a function) be treated like a
> function itself? In my specific case, I started with this expression:
> 
> code:
> --------
> (cos b * velocityC, sin b * velocityC)
> --------
> 
> But I have a compulsive hatred of duplication. I happened to have this
> function handy called appPair:
> 
> code:
> -------
> appPair f (a, b) = (f a, f b)
> 
> appPair (* velocityC) (cos b, sin b)
> -------
> 
> Better, but the b identifier is still duplicated. Is there some way I
> could have...
> 
> code:
> --------
> appPair (?) (cos, sin)
> --------
> 
> ...shifting the application of b into the (* velocityC) expression,
> without modifying my appPair function?
> 
> 
> 
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> 

Wait, think I got it...

code:
--------
appPair (\x -> (x $ b) * velocityC) (cos, sin)
--------

-- 
frigidcode.com

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