[Haskell-beginners] functional parser type error

felipe zapata tifonzafel at gmail.com
Wed Apr 4 11:54:45 CEST 2012

The parser is defined

*type Parser a = String → [(a, String)]*
But for me it is not pretty clear, why i need to
make Parser a newtype instead of working
with this one.

Can you give me some hints ?. Thanks

-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://www.haskell.org/pipermail/beginners/attachments/20120404/68a087ef/attachment.htm>

More information about the Beginners mailing list