[Haskell-beginners] functional parser type error

felipe zapata tifonzafel at gmail.com
Wed Apr 4 11:54:45 CEST 2012


Hi,
The parser is defined

*type Parser a = String → [(a, String)]*
*
*
But for me it is not pretty clear, why i need to
make Parser a newtype instead of working
with this one.

Can you give me some hints ?. Thanks

Felipe
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