[Haskell-beginners] how more efficient read/write a file ?

[Kyle Murphy]

It's not for the faint of heart, but the enumerator package is also supposed
to provide very good performance for stream transformations. I've looked at
it a bit myself but I'm still struggling to wrap my head around the types
involved, which like most things in Haskell is the key to understanding the
whole thing.

-R. Kyle Murphy
--
Curiosity was framed, Ignorance killed the cat.


On Sat, Sep 24, 2011 at 05:01, Benjamin Edwards <edwards.benj at gmail.com>wrote:

> You should look up bytestring and friends on hackage.
>
> If it is something quite simple you can use the lazy variants and provided
> that you don't try to hold onto the input you should get nice constant space
> without trying too hard.
>
> I recommend the early chapters on IO in real world haskell if you want more
> info on lazy IO.
> On 24 Sep 2011 03:06, "anyzhen" <jiangzhen3s at qq.com> wrote:
> > consider this :
> > i want load a 4G file(or some bigger file) ,and the process data
> operation just like 010 to 101( XOR bits ) , is it some efficient function
> down it ?
> > such hPutStr hPutChar is Char layer , is exist bit layer operations?
> >
> >
> > thanks for any help
> >
> >
> > jiangzhen3s at qq.com
>
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