[Haskell-beginners] Unwrap an expression?
christopher.howard at frigidcode.com
Sat Sep 3 00:23:40 CEST 2011
Perhaps this is a dumb question, but I was pondering the whole "Lazy"
aspect of Haskell, and was curious: is there someway you could create a
function "M", which you could pass an expression into, so that...
M (f (g... (n (x)) ...)) returns f
and/or returns the inner value (g... (n (x)) ...)
I don't know if that breaks the whole "referential transparency" idea or
not, but with all those lambda calculus tricks I've heard about, and the
lazy evaluation, I thought it would be worth asking.
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