[Haskell-beginners] Monads

[Patrick LeBoutillier]

Hi,

> my questions are:
>   1. is this substitution ok?
>   2. is []a = [a]?
>   3. is []b = [b]?
>
> if 2. and 3. are valid then the following is obtained:
>   fmap::(a->b)->[a]->[b]
> which is the same as map type and therefore: fmap = map. QED.
>
> Can you please answer questions 2 and 3 above?

Yes, they are equivalent. Actually both forms are valid Haskell:

a :: [Int]
a = [1]

a' :: [] Int
a' = [1]

Patrick

>
> Thank you
>
>
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-- 
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Patrick LeBoutillier
Rosemère, Québec, Canada