[Haskell-beginners] Creating beautiful code: can you make this divide-and-conquer implementation of the "tails" function beautiful?
Costello, Roger L.
costello at mitre.org
Tue Jun 28 13:43:56 CEST 2011
Thanks Michael, using the as-pattern (@) makes the algorithm cleaner:
tails' :: [a] -> [[a]]
tails' xxs@(x:y:xs) = map (++zs) (tails' ys) ++ tails' zs
where m = length xxs
n = m `div` 2
(ys,zs) = splitAt n xxs
tails' (x:[]) = [[x]]
I tried using the specific patterns you provided:
tails' :: [a] -> [[a]]
tails' xxs@(_:xs) = map (++zs) (tails' ys) ++ tails' zs
where m = length xxs
n = m `div` 2
(ys,zs) = splitAt n xxs
tails' [] = [[]]
Those patterns would make it even more elegant. However, that didn't work - the compiler went into an infinite loop. What am I missing?
Note: I am trying to clean up this divide-and-conquer algorithm, not create a different algorithm. Sorry that I wasn't clear about this in my initial message.
/Roger
From: Michael Xavier [mailto:nemesisdesign at gmail.com]
Sent: Monday, June 27, 2011 9:17 PM
To: Costello, Roger L.
Cc: beginners at haskell.org
Subject: Re: [Haskell-beginners] Creating beautiful code: can you make this divide-and-conquer implementation of the "tails" function beautiful?
I'll bite. The source of tails is pretty elegant:
tails :: [a] -> [[a]]
tails [] = [[]]
tails xxs@(_:xs) = xxs : tails xs
On Mon, Jun 27, 2011 at 1:30 PM, Costello, Roger L. <costello at mitre.org> wrote:
Hi Folks,
Below is a divide-and-conquer implementation of the "tails" function.
Notice the two patterns (x:y:xs) and (x:[]). And notice that (x:y:xs) is used by the "length" function and again by the "splitAt" function. That doesn't seem elegant. Can the function be simplified and made beautiful?
/Roger
tails' :: [a] -> [[a]]
tails' (x:y:xs) = map (++zs) (tails' ys) ++ tails' zs
where m = length (x:y:xs)
n = m `div` 2
(ys,zs) = splitAt n (x:y:xs)
tails' (x:[]) = [[x]]
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