[Haskell-beginners] problem exercise 3 page 60 Programming in Haskell

[Roelof Wobben]

Hello, 

I don't see the answer here.
If I brake down the problem.

We have this : 

[(x,y) | x <- [1..3], y <- [4,5,6]]

I have to use one generator with two nested list compreshession and make use of concat.

So the x generator  is [x | x <- [1..3]] 
and the Y genarator is [y| y <- [4..6]]

So if I put it together it uses the numbers [1..6] so I could do something like this  in pseudo code as guard.
If generator smaller or equal 3 then its x else it's a y.

But if I do concat [x,y] then I get [1..6] and that not good.
If I use zip [x,y] then I get [ (1,4) (2,5) (3,6)] which is also not good but better.

So im stuck now and im puzzeling the whole afternoon about this ?

Anyone who can give me a hint ?

Roelof

 		 	   		  
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