[Haskell-beginners] very impure [global] counter
David McBride
dmcbride at neondsl.com
Fri Jul 22 11:46:43 CEST 2011
This is what I'd do:
{-# LANGUAGE NoMonomorphismRestriction #-}
module Counter where
import Control.Monad.State
main = runStateT procedure (0 :: Integer) >> return ()
incCounter = do
n <- get
modify (+1)
return n
execFile = do
n <- incCounter
liftIO $ putStrLn $ ("command --createfile=tempfile" ++ show n ++ ".tmp")
procedure = do
execFile
execFile
liftIO $ putStrLn "do something"
execFile
On Fri, Jul 22, 2011 at 3:10 AM, Davi Santos <dps.abc at gmail.com> wrote:
> Hello all,
> I have massive (parallel if possible) system calls to an external
> non-deterministic program.
> Each time it is executed, it creates a file depending on a command line
> option 'opt' (input files path, for example).
> How can I ensure the file name will be unique? maybe with a global counter?
> My temporary solution have been to use a large random number:
> -----------
> mysteriousExecution :: String -> IO ()
> mysteriousExecution opt = do
> number <- rand
> run $ "mysterious-command " ⊕ opt ⊕ " --create-file=" ⊕ number
> rand = do
> a ← getStdRandom (randomR (1,999999999999999999999999999999999)) ∷ IO
> Int
> let r = take 20 $ randomRs ('a','z') (mkStdGen a) ∷ String
> return r
> ========
> I'm trying to avoid additional parameters to 'mysteriousExecution'.
> I tried a counter also (to replace rand), but I don't know how could I start
> it inside 'mysteriousExecution'.
> c ∷ IO Counter
> c = do
> r ← newIORef 0 -- start
> return (do
> modifyIORef r (+1)
> readIORef r)
> If somebody says everything is wrong, ok.
> I understand. 18 years of imperative programming world can damage the brain.
> Thanks
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