[Haskell-beginners] making function problem (chapter 6 of Programming in Haskell)
Roelof Wobben
rwobben at hotmail.com
Tue Aug 9 14:16:52 CEST 2011
----------------------------------------
> Date: Mon, 8 Aug 2011 14:59:39 -0700
> From: kc1956 at gmail.com
> To: beginners at haskell.org
> Subject: Re: [Haskell-beginners] making function problem (chapter 6 of Programming in Haskell)
>
> Hint
>
> positivePower :: Int -> Int -> Int
> positivePower x 1 = x
> positivePower x y = dododoo positivePower yadayada
>
>
> --
> --
> Regards,
> KC
>
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oke.
I see it
I'm going for this :
postivePower :: Int -> Int -> Int
PostivePower x 1 = 1 because when you multiply something by one is remains the same value.
PostivePower x y = x + postivePower x y
for example
x = 4
y = 3
4 * 3 =
4 + 4 * 2
4 + 4 + 4 * 1
4 + 4 + 4
4 + 8
12
Roelof
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