# [Haskell-beginners] Calling a foreign function: superlinear comlexity

David McBride dmcbride at neondsl.com
Mon Apr 11 03:53:50 CEST 2011

```The problem isn't the list or the library library.  It is the use of
the function sum, which is lazy and when you try to sum a very large
list, it makes a thunk for every single element in the list before
finally evaluating them all backwards to get the sum.

main = do
let n = 40000000
let lst = map sin [1..n]
print \$ sum' lst
where
sum' = foldl1' (+)

This is linear, repeatable and quite a bit faster.

On Sun, Apr 10, 2011 at 7:26 PM, Serguei Son <serguei.son at gmail.com> wrote:
> I call GSL's gsl_ran_ugaussian function in the following way (using
> bindings-gsl):
>
> module Main where
>
> import Bindings.Gsl.RandomNumberGeneration
> import Bindings.Gsl.RandomNumberDistributions
> import Foreign
> import Data.List
>
> main = do
>        let n = 100000
>        p <- peek p'gsl_rng_mt19937
>        rng <- c'gsl_rng_alloc p
>        lst <- replicateM n \$ c'gsl_rng_uniform rng
>        print \$ sum lst
>
> As I increase n from 10^4 to 10^5 to 10^6 execution time grows superlinearly.
>
> To forestall the answer that the reason is the overhead of List,
> this code scales approximately linearly:
>
> module Main where
>
>
> import Foreign
> import Data.List
>
> main = do
>        let n = 100000
>        let lst = map sin [1..n]
>        print \$ sum lst
>
> Another interesting observation: when I wrap the sin function
> of math.h with signature CDouble -> IO CDouble calling it
> repeatedly scales superlinearly, whereas when I wrap it as a pure
> function calling it repeatedly scales linearly.
>
> What is the reason for this performance and how can
> I make the first code scale linearly in execution time?
>
>
>
>
>
> _______________________________________________
> Beginners mailing list