[Haskell-beginners] Removing the biggest element from a list -
maybe slow?
Daniel Fischer
daniel.is.fischer at web.de
Mon May 24 10:47:50 EDT 2010
On Monday 24 May 2010 16:15:32, Markus Läll wrote:
> On a list, that is internally too a list, the complexity of the
> operation is always at least O(n), because to find the maximum, you
> have to look through all the list -- i.e do n comparisons.
>
> If you don't have any other variables like pointers to the previous
> and next elements of the maximum, when you are going trough the list
> to find it, then after finding the maximum value, you have to go
> through the list again, to find its position and remove it...
>
> For
>
> > delete (maximum xs) xs
>
> the complexity is O(n + m), where m is the index of the maximum. This
> goes through the list to find the maximum, and then goes through it
> again up until it finds the first occurrance of it.
>
> For
>
> > init $ sort xs
>
> it is (n log n) + n, where (n log n) is the complexity of the sorting
> algorithm (it might be something else depending on the algorithm), and
> (+ n) is because the init funcion has to go through the list again to
> find its last element and remove it.
And since we changed the order of elements anyway,
drop 1 $ sortBy (flip compare) xs
saves us the last traversal. But if the order is changed, it can be done in
O(n).
>
> Although Haskell is lazy, and when sorting a list, it might not get
> fully sorted until you request the last element from the sorted list,
> the init function still forces it to do so.
>
> I don't know how one would do the removing of the maximum by going
> through the list and whenever finding a bigger element, then saving
> the positions of its predecessor and successor, so it could reassemble
> the list in the middle, when it has done looking through it. Anyone
> have ideas?
remLargest :: Ord a => [a] -> [a]
remLargest [] = []
remLargest [_] = []
remLargest (x:xs) = go [] x xs
where
go post _ [] = reverse post
go post mx (y:ys)
| mx < y = mx : reverse post ++ go [] y ys
| otherwise = go (y:post) mx ys
Not as ugly as I feared, and not as inefficient for descending lists as I
feared.
More information about the Beginners
mailing list