[Haskell-beginners] parsec question

[Stephen Tetley]

On 19 July 2010 12:05, David Virebayre <dav.vire+haskell at gmail.com> wrote:

> Note that he doesn't want "123456" to parse as the integer 123456, but
> rather as the list of digits [ 1,2,3,4,5,6 ].

Fair enough, I'd swap /digitToInt/ for read though...

digit1 :: Parser Int
digit1 = liftM digitToInt digit

digitList :: Parser [Int]
digitList = many digit1

digitToInt should do less work than read - running read is effectively
re-parsing the digits you have already parsed.

Best wishes

Stephen