[Haskell-beginners] Re: multreplace

[Patrick LeBoutillier]

> multRepl = foldl (uncurry . replace)

Actually I've been thinking about this and I can't quite figure out
how it works:

I understand the type of replace is

  replace :: (Eq a) => [a] -> [a] -> [a] -> [a]

but I can't figure out how the type of (uncurry . replace) becomes

  uncurry . replace :: (Eq a) => [a] -> ([a], [a]) -> [a]

?


Patrick

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Patrick LeBoutillier
Rosemère, Québec, Canada