[Haskell-beginners] Small question

[edgar klerks]

Hi there,

I have created a function mkc:

mkc :: (a -> b) -> a -> m b
mkc f = (\x -> return $ f x)

which works wonderful in statements like:

number <- many1 digit >>= mkc(read)

But somehow I think this function should already exist, it is some kind of
lifting. If it exist where can I find it? Or is there a reason, why it isn't
in prelude, because it is more elegant way to solve this problem.

Thanks in advance,

Edgar
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