[Haskell-beginners] Type unions
Russ Abbott
russ.abbott at gmail.com
Wed Dec 15 00:29:27 CET 2010
Thanks for the references. Glad to see this isn't an unreasonable wish.
*
-- Russ *
On Tue, Dec 14, 2010 at 2:15 PM, Ozgur Akgun <ozgurakgun at gmail.com> wrote:
> This reminds me of an old thread started by, well me :)
>
> http://www.haskell.org/pipermail/haskell-cafe/2010-March/074805.html(sorry for the typos)
>
> It is not an especially enlightening thread, but contains some nice
> references.
>
> HTH,
>
> On 14 December 2010 20:09, Russ Abbott <russ.abbott at gmail.com> wrote:
>
>> Is there a way to get this to work?
>>
>> data A = Aconstructor Int
>> data B = Bconstructor Int
>> data AorB = A | B
>>
>> f :: Int -> AorB
>> f x
>> | even x = Aconstructor x
>> | otherwise = Bconstructor x
>>
>> I get this diagnostic.
>>
>> Couldn't match expected type `AorB' against inferred type `A'
>>
>>
>> Since AorB is A or B, why is this not permitted?
>>
>> If instead I write
>>
>> data AorB = Aconstructor Int | Bconstructor Int
>>
>>
>> everything works out ok. But what if I want separate types for A and B?
>>
>> Thanks,
>> *
>> -- Russ *
>>
>>
> --
> Ozgur Akgun
>
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