[Haskell-beginners] Re: Forcing evalation in the IO Monad
Daniel Fischer
daniel.is.fischer at web.de
Fri Apr 16 15:27:10 EDT 2010
Am Freitag 16 April 2010 17:09:07 schrieb Philip Scott:
> Philip Scott wrote
>
> > The documentation says that, but it does appear to go deeper than just
> > one level:
> >
> > Debug.Trace Prelude Control.Exception> let a = trace "Hello" 42
> > Debug.Trace Prelude Control.Exception> let b = trace "Frank" (a * 2)
> > Debug.Trace Prelude Control.Exception> evaluate b
> > Frank
> > Hello
> > 84
> >
> > Perhaps it specifies WHNF in case you 'evaluate' something which
> > doesn't have a HNF (like a partially applied function?).
>
> It is actually quite interesting what it does in this case:
> > let f x = trace "jingle" (x * 2)
> > a <- evaluate (f)
> >
> > :t f
>
> f :: (Num a) => a -> a
>
> > :t a
>
> a :: Integer -> Integer
>
> So it does some sort of evaluation - it has decided we're going to be
> using Integers instead of Nums. I wonder what it is up to there.
Without impredicative polymorphism (whatever that is), you can't get a
polymorphic value from an action, so while
Prelude Debug.Trace Control.Exception> :t evaluate f
evaluate f :: (Num a) => IO (a -> a)
, when you bind the result of evaluate f to a name, that is assigned a
monomorphic type. Without a type signature, the type variable a is
defaulted to Integer. You can (until 6.14)
Prelude Debug.Trace Control.Exception> :set -XImpredicativeTypes
Prelude Debug.Trace Control.Exception> u <- evaluate f :: IO (forall a. Num
a => a -> a)
<no location info>:
Warning: -XImpredicativeTypes is deprecated: impredicative polymorphism
will be simplified or removed in GHC 6.14
Prelude Debug.Trace Control.Exception> :t u
u :: (Num a) => a -> a
Prelude Debug.Trace Control.Exception> u 4 :: Int
jingle
8
Prelude Debug.Trace Control.Exception> u 4 :: Double
jingle
8.0
Prelude Debug.Trace Control.Exception> u 4 :: Rational
jingle
8 % 1
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