[Haskell-beginners] Re: map question

Will Ness will_n48 at yahoo.com
Sun Oct 18 07:11:07 EDT 2009

Brent Yorgey <byorgey <at> seas.upenn.edu> writes:

> On Sat, Oct 17, 2009 at 06:29:39PM +0000, Will Ness wrote:
> > 
> > Then why wouldn't (`-`1) parse at at all? And not even (`(-)`1) ?
> > 
> > I know this doesn't parse, my question is, why wouldn't it be made valid 
> > syntax? It seems consistent. (`mod`2) parses, why not (`-`2) ?
> `backticks` are only for making (prefix) functions into (infix)
> operators.  - is already an infix operator, so putting it in backticks
> would be redundant.  As for `(-)`, arbitrary expressions cannot go
> inside backticks, and for good reason: what would `(2 `mod`)` parse
> as?  
> However, certainly different choices might have been possible.
> -Brent

backticks could've been made no-op for operators. What's so wrong with (`:`[])? 
It'd just be the same as (:[]).

Except for `-`, where it would finally provide us with possibility to write a 
shortcut for the ugly (flip (-) 1) as (`-`1).

(2`mod`) is a unary operation :: (Integral a) => a -> a. Putting it inside 
backticks would require it be a binary infix op, causing a type mis-match.

For (-) it could choose the binary version over the unary. 

Or it could stay illegal for the parenthesised expressions, and just made legal 
syntax for operators, as (`:`[]). 

I don't know how easy or even possible it is to implement; I'm just saying it 
makes sense, for me.

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