[Haskell-beginners] parse error

[Felipe Lessa]

On Sun, Oct 04, 2009 at 04:11:35PM +0200, informationen wrote:
> the "| True" part is wrong. It should read:
>
> is_even n   | n `mod` 2 == 0 = True
>             | otherwise = False.

Which means that is_even may be expressed as

is_even n = n `mod` 2 == 0


Equivalently, in C the first code would be

int is_even(int n) {
  if (n % 2 == 0)
    return 1;
  else
    return 0;
}

while the code I presented above would be

int is_even(int n) {
  return (n % 2 == 0);
}


HTH,

--
Felipe.