[Haskell-beginners] Re: Haskell Generic Function Question

[Ertugrul Soeylemez]

Jeff Wheeler <jeff at nokrev.com> wrote:

> > f = \x -> (x `quot` 10, x `mod` 10)
>
> Your function f is almost the same as divMod in Prelude. Also, using a
> lambda function seems odd; this is simpler:
>
> > f x = (x `quot` 10, x `mod` 10)

Hmm, simplicity.

  f = (`quot` 10) &&& (`mod` 10)

SCNR.


Greets,
Ertugrul.


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