[Haskell-beginners] defining 'init' in terms of 'foldr'
Michael Mossey
mpm at alumni.caltech.edu
Mon May 11 10:13:36 EDT 2009
In S. Thompson's book, problem 9.13 asks us to define 'init' in terms of
foldr. I was baffled at first because I didn't see a natural way to do
this. It would look something like
init xs = foldr f initialValue xs
where f would cons on each character except the rightmost.
f <when passed rightmost char> b = []
f <when passed any other char a> b = a : b
How does f "know" when it is passed the first character? initialValue has
to signal this somehow. On #haskell, one person suggested doing it with
some post-processing:
init xs = snd $ foldr f (True,[]) xs
where f _ (True,_) = (False,[])
f a (False,b) = (False,a:b)
I had an idea. If the initial value is the entire list, then its length can
function as the "signal" that we are dealing with the rightmost char. This
requires no post-processing:
init xs = foldr f xs xs
where f a b | length b == length xs = []
| otherwise = a:b
These seem contrived. I wonder if there is a more natural solution that
Thompson had in mind. Any comments?
-Mike
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