[Haskell-beginners] Compile type Error
emmanuel.delaborde
emmanuel.delaborde at cimex.com
Thu Jan 29 11:28:10 EST 2009
On 29 Jan 2009, at 16:10, beginners-request at haskell.org wrote:
> Content-Type: text/plain; charset="iso-8859-1"
>
> I didn't compile, but, by the looks of it, I would change
>
> import qualified Data.ByteString as BS (readFile)
>
> for
>
> import qualified Data.ByteString.Lazy as BS (readFile)
>
>
> as it seems sha1 needs a lazy bytestring
Thanks !
It compiles now but brings me to my real problem :)
If I uncomment this line
"md5" -> md5sum
I get the following :
------
module Main where
import System.Environment (getArgs)
import Data.Digest.OpenSSL.MD5 (md5sum)
import Data.Digest.Pure.SHA (sha1, showDigest)
import qualified Data.ByteString.Lazy as BS (readFile)
-- sha1 :: ByteString -> Digest
-- readFile :: FilePath -> IO ByteString
-- md5sum :: ByteString -> String
-- showDigest :: Digest -> String
checkHash :: String -> String -> String -> IO ()
checkHash codec hash file =
let f = case codec of
"md5" -> md5sum
"sha1" -> showDigest . sha1
_ -> error "Codec must be md5 or sha1 !" in
BS.readFile file >>= \fileBS ->
let fileHash = f fileBS in
print (hash == fileHash)
main =
getArgs >>= \as ->
case as of
(codec:hash:file:_) -> checkHash codec hash file
_ -> usage
usage = print "checksum codec hash file"
------
which now fails to compile with this error :
checksum.hs:17:22:
Couldn't match expected type `Data.ByteString.Internal.ByteString'
against inferred type
`Data.ByteString.Lazy.Internal.ByteString'
In the expression: showDigest . sha1
In a case alternative: "sha1" -> showDigest . sha1
In the expression:
case codec of {
"md5" -> md5sum
"sha1" -> showDigest . sha1
_ -> error "Codec must be md5 or sha1 !" }
How can I both use md5sum and sha1 when one use a lazy ByteString end
the other one does not ?
Thanks
E
--
Emmanuel Delaborde
Web Technologist
Cimex
53-55 Scrutton Street, London UK, EC2A 4PJ
T: +44 (0)20 7324 7780
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