[Haskell-beginners] Re: Sequential IO processing
Heinrich Apfelmus
apfelmus at quantentunnel.de
Thu Feb 19 10:32:29 EST 2009
Sergey V. Mikhanov wrote:
> I tried this earlier as well:
>
> sequenceIO [] = return []
> sequenceIO (x : xs) = do result <- x
> resultTail <- sequenceIO xs
> return result : resultTail
The last line should be
return (result : resultTail)
otherwise it will be parsed as
(return result) : resultTail
which is not what you want.
Regards,
apfelmus
--
http://apfelmus.nfshost.com
More information about the Beginners
mailing list