[Haskell-beginners] Palindromic solution??

[Thomas Davie]

On 16 Feb 2009, at 19:30, Dave Bayer wrote:

> Here's a solution harder on the machine, easier on the brain:
>
> isPalindrome :: Eq a => [a] -> Bool
> isPalindrome xs = and $ zipWith (==) xs $ reverse xs

Lets just tidy that up a little...
isPalindrome = (and . zipWith (==)) <*> reverse

But I don't see how either is easier on the brain than xs == reverse xs.

Bob