[Haskell-beginners] Simplifying a 'split' function
Ben Sanders
bwsanders at gmail.com
Wed Apr 29 15:00:59 EDT 2009
In looking through a merge sort implementation example, I came across this code:
split :: [a] -> [[a]]
split [] = []
split (x:xs) = [x] : split xs
I would have written the same code as
split :: [a] -> [[a]]
split = map (: [])
Is there any particular difference here (other than explicit
recursion)? And is there any other nicer way to write it?
Thanks,
Ben Sanders
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