[Haskell-beginners] short function to remove and replace an item

[Michael P Mossey]

What if I have a list xs, and I want to remove one item and replace it 
with another? The item to remove can be detected by a predicate 
function. The order of the items doesn't matter. How about this:

replaceItem :: (a -> Bool) -> a -> [a] -> [a]
replaceItem p new xs = new : snd (partition p xs)

This will actually replace all items that match the predicate with one 
copy of 'new'. It will also prepend 'new' even if no items match the 
predicate.

For another challenge, can someone explain to me how to write this in 
point-free style?

Thanks,
Mike