[Haskell-beginners] evaluation of expressions [was Re: eval
command?]
Andrew Sackville-West
andrew at swclan.homelinux.org
Tue Oct 28 20:20:12 EDT 2008
On Tue, Oct 28, 2008 at 07:00:00PM -0400, Tony Hannan wrote:
> On Mon, Oct 27, 2008 at 11:26 PM, Brandon S. Allbery KF8NH <
> allbery at ece.cmu.edu> wrote:
>
> > On 2008 Oct 27, at 23:25, Andrew Sackville-West wrote:
> >
> >> this raises a question for me, being a bit of a schemer. Is there any
> >> parallel in haskell to the data is code model of the lisp family? For
> >> example, playing around in scheme with a symbolic differentiator, it
> >> is trivial to then evaluate the differentiated s-expression at
> >> arbitrary value by representing the expression, and it's derivative as
> >> a regular scheme expression.
> >>
> >> Is this something that can be done in haskell? My initial impression
> >> is no, that you'd have to parse it as an expression and evaluate it as
> >> you would in regular imperative languages. I'd love to hear otherwise.
> >>
> >
> >
> > You get this in a type-safe form with Template Haskell; you can operate on
> > expressions at the AST level.
> >
> >
> Yeah, but can you do this at run time? I though Template Haskell can only be
> used at compile time.
That's what I'm talking about, run time evaluation of code/data. In
scheme, I can take as input
(+ (exp x 2) (* 2 x))
a representation of x^2 + 2x
I can feed that "data" into a function
(derive input)
and get back
(+ (* 2 x) 2)
a representation of 2x +2, the derivative of the above. The function
derive can manipulate that "Data" which is just a list, or
s-expression like any other data (for example accessing the first
element in the list, determining that it's a '+' and so calling derive
recursively on the two following elements).
then I can feed that result into (eval) with some information about
what the value of x is and it will be evaluated just like a regular
scheme expression. something like (it's been a while):
(let ((x 2))
(eval default-environment (derive (input))))
where default-environment lets you get the information about the
current environment into the eval environment so that x has a
value. So now, what was "Data" a moment ago is treated as executable
within the eval.
The above (let) would spit out(in this case) a value of 6.
Is such a thing possible in haskell?
(I'm really just curious, I have no need of this functionality at this
point). Oh, and I apologise for the fingernail clippings...
A
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