[Haskell-beginners] Re: Function composition with more than 1 parameter

[Glurk]

> The lambdabot on #haskell has a plugin named "pointless" that can
> transform this into a definition that doesn't mention  x  and  xs
> anymore. I think it will propose
> 
>   howMany = (length .) . matches
> 
> And with
> 
>   matches x xs = filter (x==) xs
> 
>   matches x    = filter (x==)
> 
>   matches      = filter . (==)
> 
> we have
> 
>   howMany = (length .) . filter . (==)

> 
>   howMany = curry (length . uncurry matches)


Thanks apfelmus,

unfortunately, none of those suggested changes seem to work !
I get errors like :-

Unresolved top-level overloading
*** Binding             : howMany2
*** Outstanding context : Eq b

I'm using WinHugs - do you get them to work in some other environment ?

Thanks ! :)