[Haskell-beginners] bottom case in proof by induction

raeck at msn.com raeck at msn.com
Wed Dec 31 16:58:48 EST 2008

Dear all,

Happy New Year!

I am learning the Induction Proof over Haskell, I saw some proofs for the equivalence of two functions will have a case called 'bottom' but some of them do no have.  What kind of situation we should also include the bottom case to the proof? How about the functions do not have the 'bottom' input such as:

foo [] = []
foo (x:xs) = x : (foo xs)

thank you,

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