[Haskell-beginners] Reading input
Yitzchak Gale
gale at sefer.org
Wed Aug 20 16:31:16 EDT 2008
Hi Barry,
Barry Burd wrote:
> median :: [Int] -> Int
> median lst =
> case medians lst of
> -- All the values in the result are the same, we just pick the first one
> x:xs -> x
>
> main = do
> putStr "Enter a list: "
> lst <- getLine
> median lst
> I'm sure this is because Haskell isn't automatically changing a String
> to a List of numbers. But how can I do this?
Use the "read" function. Watch out, though - there is
no error checking there. So if the user enters a string
that does not have the right syntax for a Haskell list
of integers, your program will halt with an error message.
You have another problem - you used the "median"
function as a step in a do block - but each step in a
do block must have type "IO a" for some type a.
Here's how you could write your main function:
main = do
putStr "Enter a list: "
lst <- getLine
print $ median $ read lst
Regards,
Yitz
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