[Haskell] semantice of seq

[roconnor at theorem.ca]

Would the problematic semantics of seq be resolved if seq did nothing on 
function types?  That is to say

seq (\x -> undefined `asTypeOf` x) y reduced to y

and

seq (undefined `asTypeOf` id) y also reduced to y


-- 
Russell O'Connor                                      <http://r6.ca/>
``All talk about `theft,''' the general counsel of the American Graphophone
Company wrote, ``is the merest claptrap, for there exists no property in
ideas musical, literary or artistic, except as defined by statute.''