[Haskell-cafe] Eval forgotten unless type specified?

[Jeffrey Brown]

In this passage, after the seq call, :sprint reveals x and y to be
evaluated:
let x = 1 + 2 :: Int
let y = x + 1
:sprint x
:sprint y
seq y ()
:sprint x
:sprint y

The above is a verbatim quote of Marlow's Concurrency book, chapter 2.

In the below, however, :sprint shows them unevaluated both before and after
the seq call.
let x = 1 + 2
let y = x + 1
:sprint x
:sprint y
seq y ()
:sprint x
:sprint y

Why?
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