[Haskell-cafe] Re: instance Eq (a -> b)

[Jonas Almström Duregård]

> f,g :: Bool -> Int
> f x = 6
> g x = 6
>
> We can in Haskell compute that these two functions are equal, without solving the halting problem.

Of course, this is the nature of generally undecidable problems. They
are decidable in some cases, but not in general.

/Jonas

2010/4/14 Thomas Davie <tom.davie at gmail.com>:
>
> On 14 Apr 2010, at 09:01, Jonas Almström Duregård wrote:
>
>>> But if one did start considering bottom to be a value, one would have to
>>> distinguish different ones. For instance, (error "ABC") vs. (error
>>> "PQR"). Obviously this is not finite.
>>
>> Nor is it computable, since it must distinguish terminating programs
>> from nonterminating ones (i.e. the halting problem).
>>
>> On a side note, since "instance (Finite a, Finite b) => Finite (a ->
>> b)" should be possible, one can even compare some higher order
>> functions with this approach ;).
>
> f,g :: Bool -> Int
> f x = 6
> g x = 6
>
> We can in Haskell compute that these two functions are equal, without solving the halting problem.
>
> Bob