[Haskell-cafe] Newbie question: Why gfoldl has this strange type?

[Ryan Ingram]

Actually, it's a higher rank type and that doesn't show up on hoogle's main
page.

gfoldl :: (forall a b . Data a => c (a -> b) -> a -> c b)
    -> (forall g . g -> c g)
    -> a
    -> c a
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