[Haskell-cafe] Re: Non-technical Haskell question

[Sven Panne]

Jules Bean wrote:
> I don't think it does, actually. You can imagine a compiler which has 
> access to not *only* the .so files, but also the haskell source. 
> Therefore it can still unroll (from the source), but it can choose to 
> link to an exported symbol if unrolling isn't worth it.

But that's not dynamic linking... Imagine a bug in version X of your lib,
simply using version X+1 with your already compiled program won't fix that
bug. Again, this is just like C++.

Cheers,
    S.