Re: [GHC] #11553: `round (± ∞ :: Double)` not infinite

GHC ghc-devs at haskell.org
Sun Feb 7 09:01:01 UTC 2016


#11553: `round (± ∞ :: Double)` not infinite
-------------------------------------+-------------------------------------
        Reporter:  hvr               |                Owner:
            Type:  bug               |               Status:  new
        Priority:  normal            |            Milestone:
       Component:  libraries/base    |              Version:
      Resolution:                    |             Keywords:
Operating System:  Unknown/Multiple  |         Architecture:
 Type of failure:  Incorrect result  |  Unknown/Multiple
  at runtime                         |            Test Case:
      Blocked By:                    |             Blocking:
 Related Tickets:                    |  Differential Rev(s):
       Wiki Page:                    |
-------------------------------------+-------------------------------------
Description changed by hvr:

@@ -1,1 +1,1 @@
- Rounding 1/0 or 0/0 results in an arbitrary chosen `Integer` value, e.g.
+ Rounding 1/0 or -1/0 results in an arbitrary chosen `Integer` value, e.g.
@@ -9,0 +9,3 @@
+
+ λ:4> (round (0/0 :: Double) :: Integer)  == -(2^1024 + 2^1023)
+ True

New description:

 Rounding 1/0 or -1/0 results in an arbitrary chosen `Integer` value, e.g.

 {{{
 λ:2> (round (1/0 :: Double) :: Integer)  == 2^1024
 True

 λ:3> (round (-1/0 :: Double) :: Integer)  == -(2^1024)
 True

 λ:4> (round (0/0 :: Double) :: Integer)  == -(2^1024 + 2^1023)
 True
 }}}

 I'm not sure if this is more desirable than returning a bottom value (e.g.
 by throwing some `ArithException`)

--

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Ticket URL: <http://ghc.haskell.org/trac/ghc/ticket/11553#comment:1>
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