[Haskell-beginners] GCJ 2015 - Round 1A Problem - Haircut

Sumit Sahrawat, Maths & Computing, IIT (BHU) sumit.sahrawat.apm13 at iitbhu.ac.in
Sat Apr 18 15:51:49 UTC 2015


The link doesn't work because the hyperlink doesn't include the apostrophe
at the end.
Also, I'm sorry for having written off foldr as being worthless, I didn't
think much about it when I replied.

Foldl is the bad one here, whereas foldr and foldl' are both good and
recommended options.
Foldr can cause stack overflow as it also creates unevaluated thunks, but
then you can use foldl' to get over that.

How did it go with strict foldl?

On 18 April 2015 at 21:04, Sourabh <sourabh.s.joshi at gmail.com> wrote:

> Thanks Sumit, I changed my folds to a strict foldl'. I'll check how long
> it runs now.
>
> Doug, I think you are absolutely correct. Taking the harmonic mean
> probably factored into the solution, in order to make it algorithmically
> feasible for the large input! Lesson learnt, next time I'll probably think
> harder about the problem than the code ;)
>
> On Sat, Apr 18, 2015 at 7:29 AM, Doug McIlroy <doug at cs.dartmouth.edu>
> wrote:
>
>> > Can someone tell me how I could have avoided or fixed this?
>>
>> The trouble manifested as stack overflow on solving
>>
>> > https://code.google.com/codejam/contest/4224486/dashboard#s=p1
>>
>> For efficiency, you'll probably need more cleverness in math than
>> in Haskell. You can predict an approximate start time for the Nth
>> customer's service from the average per-customer service time M,
>> where 1/M = sum 1/M_k.
>> Starting from that estimate, one can skip over almost the entire
>> service simulation.
>>
>> Doug McIlroy
>>
>
>
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-- 
Regards

Sumit Sahrawat
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